Final answer:
The measure of exterior angle ∠ZAB of triangle ABC is proven to be equal to the sum of the measures of the non-adjacent interior angles ∠ACB and ∠CBA using the Triangle Exterior Angle Theorem and substitution.
Step-by-step explanation:
The solution to the student's problem involves applying the Triangle Exterior Angle Theorem, which states that the measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent internal angles.
In this case, angle ∠ZAB is an exterior angle and, by the theorem, m∠ZAB = m∠ACB + m∠CBA. This effectively proves that the measure of the exterior angle is equal to the sum of the measures of the interior opposite angles.
Additionally, angles ZAB and CAB form a linear pair which sum to 180° because of properties of a straight line. Since m∠CAB + m∠ACB + m∠CBA = 180° (angle sum property of a triangle), and combining this with the previous statement, we can conclude that m∠ZAB = m∠ACB + m∠CBA, hence proving the initial statement using substitution.