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Answer for top box (1)? And for the bottom box (2)?

Answer for top box (1)? And for the bottom box (2)?-example-1
User Madsobel
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The solution to the first equation is v = 1, and the correct statement is "V = 1".

The only solution to the equation is u = 1/3.

Let's analyze each equation to determine its solution and the corresponding statement:

Equation 1:

4(v + 2) + 2 = 2(v + 6)

Expanding the left side:

4v + 8 + 2 = 2v + 12

Combining like terms:

6v + 10 = 2v + 12

Subtracting 2v from both sides:

4v + 10 - 2v = 2v + 12 - 2v

2v + 10 = 12

Subtracting 10 from both sides:

2v + 10 - 10 = 12 - 10

2v = 2

Dividing both sides by 2:

2v/2 = 2/2

v = 1

Therefore, the solution to the first equation is v = 1, and the correct statement is "V = 1".

Equation 2:

3(2+u) u = 6 + 2(u + 1)

Expanding the left side:

6u + 3u^2 = 6 + 2u + 2

Combining like terms:

3u^2 + 4u - 4 = 0

Factoring the expression:

(u + 4)(3u - 1) = 0

Therefore, either u + 4 = 0 or 3u - 1 = 0. Solving for u in each case:

u + 4 = 0, so u = -4

3u - 1 = 0, so u = 1/3

However, the original equation is undefined when u = -4. Therefore, the only solution to the equation is u = 1/3, and the correct statement is "u = 1/3".

User Ajbeaven
by
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