Final answer:
The fish population two years before the first survey in 2005 was more than 1000, calculated using the equation p = 5000(2)^t with t = -2.
Step-by-step explanation:
The question provided involves determining whether the invasive fish population in a lake was more or less than 1000, two years before the first survey in 2005, using the given population growth equation p = 5000(2)^t. To solve this, you would plug t = -2 into the equation, which results in p = 5000(2)^{-2} = 5000(1/4) = 1250. Thus, the fish population for t = -2 is more than 1000.