72.2k views
4 votes
How long will it take a $6000 investment to grow to 6924 at an annual rate of 9.8%, compounded semiannually?

User Zulu Z
by
7.1k points

1 Answer

6 votes

Final answer:

Using the compound interest formula, we find that a $6000 investment will take approximately 3 years to grow to $6924 at an annual rate of 9.8%, compounded semiannually.

Step-by-step explanation:

To determine how long it will take for a $6000 investment to grow to $6924 at an annual rate of 9.8%, compounded semiannually, we use the compound interest formula:

A = P(1 + r/n)(nt)

Where:

  • A is the amount of money accumulated after n years, including interest.
  • P is the principal amount (the initial amount of money).
  • r is the annual interest rate (decimal).
  • n is the number of times that interest is compounded per year.
  • t is the time the money is invested or borrowed for, in years.

Given:

  • A = $6924
  • P = $6000
  • r = 9.8% or 0.098
  • n = 2 (since the interest is compounded semiannually)

Plugging in these values, we solve for t:

$6924 = $6000(1 + 0.098/2)(2t)

After some calculations, we find:

1.154 = (1 + 0.049)(2t)

t = ln(1.154) / (2 * ln(1.049))

After calculating using a calculator, we find that t is approximately 3 years.

Therefore, it will take approximately 3 years for a $6000 investment to grow to $6924 at an annual rate of 9.8%, compounded semiannually.

User Mohsen Nosratinia
by
8.2k points