Question

In an inelastic collision, a bullet of mass 0.03 kg traveling at 100 m/s lodges into a 2.00 kg block of wood hanging at rest from two ropes on the ceiling. What is the total kinetic energy of the bullet and wood before the bullet hits the wooden block?In an inelastic collision, a bullet of mass 0.03 kg traveling at 100 m/s lodges into a 2.00 kg block of wood hanging at rest from two ropes on the ceiling. What is the total kinetic energy of the bullet and wood before the bullet hits the wooden block?

Answer 1

The total kinetic energy of the bullet and wood before the collision is 150 Joules, as only the bullet is moving, and the wood block is at rest.

Step-by-step explanation:

The total kinetic energy of the bullet and wood before the bullet hits the wooden block can be calculated using the kinetic energy formula KE = 1/2 mv², where m is the mass and v is the velocity of the bullet. Since the block of wood is at rest, its kinetic energy is zero. Therefore, we only need to calculate the kinetic energy of the bullet.

Kinetic energy of bullet = 1/2 * 0.03 kg * (100 m/s)²

Kinetic energy of bullet = 1/2 * 0.03 kg * 10000 m²/s²

Kinetic energy of bullet = 1/2 * 0.03 kg * 10000 m²/s² = 150 Joules

So, the total kinetic energy of the bullet and wood before the collision is 150 Joules.