Final answer:
To find the mass of PbSO₄ produced from 23.6 g of PbO₂, use stoichiometry. The mass of PbSO₄ produced is 60.04 g.
Step-by-step explanation:
To find the number of grams of PbSO₄ produced from the complete reaction of 23.6 g of PbO₂, we need to use stoichiometry.
From the balanced chemical equation:
1 mol of PbO₂ reacts with 2 mol of H₂SO₄ to produce 2 mol of PbSO₄
Using the molar masses of PbO₂ and PbSO₄, we can convert the mass of PbO₂ to moles and then use the stoichiometric ratio to find the mass of PbSO₄ produced:
23.6 g PbO₂ * (1 mol PbO₂ / 239.2 g PbO₂) * (2 mol PbSO₄ / 1 mol PbO₂) * (303.27 g PbSO₄ / 1 mol PbSO₄) = 60.04 g PbSO₄