Question

3 toy racing cars, car A, car B, and car C went racing on a track. Car A completed one round in 10 seconds. Car B ran the same round in 12 seconds, and car C took 15 seconds to complete the race. If the cars started the race at the same time, find:

(A) The time lapsed when the 3 cars met,
(B) The number of complete rounds made by car C when the 3 cars met.

Answer 1

The three toy racing cars met after 60 seconds, which is when Car C had completed 4 complete rounds on the track.

Step-by-step explanation:

To find the time lapsed when all 3 cars met on the track after starting the race together, we need to calculate the least common multiple (LCM) of the time taken by each car to complete one round of the track. Car A completes a round in 10 seconds, Car B in 12 seconds, and Car C in 15 seconds.

The LCM of 10, 12, and 15 is 60 seconds. This is the time when all three cars would meet at the starting point, having completed multiple rounds each: Car A would complete 6 rounds, Car B 5 rounds, and Car C 4 rounds.

To determine the number of complete rounds made by Car C when all 3 cars met, we divide the LCM by the time Car C takes for one round. So, Car C makes 60 seconds ÷ 15 seconds per round = 4 complete rounds.