Final answer:
Using the stoichiometry of the balanced chemical equation and the molar masses of Hg and HgO, 44 g of Hg will produce approximately 48 g of HgO when reacting with excess O2. None of the answer choices provided (A. 72 g, B. 88 g, C. 96 g, D. 112 g) match this correct result, indicating a potential error in the question.
Step-by-step explanation:
To determine how many grams of HgO will be produced from 44 g of Hg reacting with excess O2, we will need to use the stoichiometry of the balanced chemical equation provided: 2Hg (l) + O2(g) → 2HgO (s). First, we calculate the molar mass of Hg, which is approximately 200.59 g/mol. Then, we find the molar mass of HgO, which is approximately 200.59 g/mol for Hg + 16.00 g/mol for O, equaling 216.59 g/mol for HgO. Using stoichiometry, we set up a conversion:
(44 g Hg) x (1 mol Hg / 200.59 g Hg) x (1 mol HgO / 1 mol Hg) x (216.59 g HgO / 1 mol HgO).
This calculation yields the mass of HgO produced when 44 g of Hg react with excess O2.
The calculation gives: (44 / 200.59) x 216.59 g HgO, which equals approximately 48 g of HgO. This result is not present in the multiple-choice options provided, which suggests there may be a typo or error in the question or options given.