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If a ball goes from rest to 15m/s in .41s, what is the acceleration of the ball?

(A) 36.58m/s²
(B) 36.58m/s
(C) 15m/s²
(D) 15m/s

1 Answer

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Final answer:

The acceleration of the ball, which goes from rest to 15m/s in 0.41s, is calculated using the formula a = Δv / Δt. The result is approximately 36.59 m/s², so the correct answer is (A) 36.58 m/s².

Step-by-step explanation:

To find the acceleration of the ball, we will use the formula for acceleration, which is a change in velocity divided by the time it takes for that change to occur. In this case, the ball starts from rest and reaches a velocity of 15 m/s in a time period of 0.41 seconds. The formula to use is: a = Δv / Δt

Where:Since the initial velocity is 0 (ball starts from rest), the change in velocity (Δv) is 15 m/s. The time (Δt) is 0.41 s. Plugging these values into our formula gives us:

a = (15 m/s - 0 m/s) / 0.41 s = 15 m/s / 0.41 s

After calculating the above expression, we find that the acceleration (a) is approximately 36.59 m/s². So the correct answer is (A) 36.58 m/s².

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