58.8k views
1 vote
What is the standard form of the equation of a parabola that has a vertex of (-1,10) and passes through the point (2,-8)?

A) y = 2(x + 1)² + 10
B) y = 2(x - 1)² + 10
C) y = -2(x + 1)² + 10
D) y = -2(x - 1)² + 10

User Ptrck
by
8.6k points

1 Answer

4 votes

Final answer:

The standard form of a parabola with a vertex at (-1,10) and passing through (2,-8) is y = -6(x + 1)² + 10, which doesn't match any of the provided options.

Step-by-step explanation:

The standard form of a parabola's equation is given by y = a(x - h)² + k, where (h, k) is the vertex of the parabola. Given the vertex (-1,10) and that the parabola passes through the point (2,-8), we can substitute these values into the equation to find the coefficient a.

Using the vertex, the equation becomes y = a(x + 1)² + 10. Substituting the point (2, -8) into this equation yields -8 = a(2 + 1)² + 10. Solving for a gives us a = -6. The correct standard form equation of the parabola is then y = -6(x + 1)² + 10, which is not one of the options provided, meaning there may be an error in the question or options.

User TopperH
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.