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Express the product of (x - 2) and (x² – 3x + 8) in standard form.

(A) x³ - 3x² + 8x - 2x² + 6x - 16
(B) x³ - 5x² + 14x - 16
(C) x² - 5x + 14
(D) x² - 3x + 8

1 Answer

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Final answer:

The product of (x - 2) and (x² – 3x + 8) is x³ - 5x² + 14x - 16, which is found by distributing each term in the first polynomial across each term in the second polynomial and combining like terms.

Step-by-step explanation:

To express the product of (x - 2) and (x² – 3x + 8) in standard form, we use the distributive property to multiply each term in the first polynomial by each term in the second polynomial:

  • Multiply x by to get
  • Multiply x by -3x to get -3x²
  • Multiply x by 8 to get 8x
  • Multiply -2 by to get -2x²
  • Multiply -2 by -3x to get 6x
  • Multiply -2 by 8 to get -16

Combine like terms:

  • stays the same.
  • Add -3x² and -2x² together to get -5x²
  • Add 8x and 6x to get 14x
  • <-16> stays the same.

The product in standard form is x³ - 5x² + 14x - 16, which corresponds to answer choice (B).

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