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Tickets to a play cost $4 in advance and $5 at the door. The theater club president wants to raise at least $400 from the ticket sales. Write an inequality for the number of tickets the theater club needs to sell. If the club sells 40 tickets in advance, what is the least number the club needs to sell at the door to reach the president’s goal?

User Shihan
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Final answer:

The theatre club needs to sell tickets such that their total revenue is at least $400, with inequality $4a + $5d ≥ $400. If 40 tickets are sold in advance, at least 48 tickets must be sold at the door to meet the goal.

Step-by-step explanation:

To write an inequality for the number of tickets the theater club needs to sell to raise at least $400, let's denote the number of advance tickets as a and the number of tickets sold at the door as d. Since tickets cost $4 in advance and $5 at the door, the inequality representing the total revenue R would be $4a + $5d ≥ $400.

If the club sells 40 tickets in advance, we can substitute a = 40 into the inequality to find out the least number of tickets they need to sell at the door. The revenue from the advance tickets is $4 × 40 = $160. Subtracting this from the $400 goal, we have $400 - $160 = $240 needed from door sales. Thus, the inequality becomes $5d ≥ $240, and solving for d yields d ≥ $240/$5, so d ≥ 48.

Therefore, the theater club needs to sell at least 48 tickets at the door to meet their goal, assuming they sell 40 tickets in advance.

User XSkrappy
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