Question

A store sells chocolate candy for $2.00 each. During the first hour the store was open, x chocolate candies were sold. During the second hour, the store sold 5 fewer chocolate candies than it sold during the first hour. During the third hour, it sold three times as many chocolate candies as it sold during the second hour. The store was paid a total of $120.00 for the chocolate candies sold during these three hours. The equation shown below represents these sales.2x + 2(x + 5) + 3 x 2(x+5) = 120.How much money was the store paid for chocolate candies sold during the third hour it was open?

A. $10
B. $15
C. $20
D. $25

Answer 1

The correct total revenue generated by the store during the third hour is $66.00, achieved by selling 33 chocolate candies at $2.00 each.

Step-by-step explanation:

The equation provided in this problem is incorrect and does not properly reflect the situation described. To find the correct equation, we first identify what the variables represent. Let x be the number of chocolate candies sold in the first hour. Thus, x - 5 is the amount sold in the second hour, and 3(x - 5) is the amount sold in the third hour. Each candy is sold for $2.00. The total revenue for the three hours is given as $120.00. The correct equation to represent the total sales would be:

2x + 2(x - 5) + 2 × 3(x - 5) = 120

Simplifying the equation, we get:

2x + 2x - 10 + 6x - 30 = 120

Combining like terms gives us:

10x - 40 = 120

Adding 40 to both sides, we have:

10x = 160

Dividing both sides by 10 gives us:

x = 16

To find how much was made in the third hour, we need to calculate the number of chocolates sold in the third hour, which is 3 times the amount sold in the second hour:

3(x - 5) = 3(16 - 5) = 3(11)

This gives us:

33 chocolates sold in the third hour.

Since each chocolate is sold for $2.00, the revenue from the third hour is:

33 × $2.00 = $66.00

Therefore, the store was paid $66.00 for the chocolate candies sold during the third hour it was open.