Final answer:
The amount of isopropyl alcohol and water in the 30.0% (v/v) alcohol solution, multiply the percentage by the total volume of the solution. In 845 mL of the solution, there are approximately 253.5 mL of isopropyl alcohol and 591.5 mL of water.
Step-by-step explanation:
To find the amount of isopropyl alcohol and water in the 30.0% (v/v) alcohol solution, we can use the concept of volume percentage. In a 30.0% (v/v) solution, 30.0 mL of isopropyl alcohol is present in 100 mL of solution. In a total of 845 mL of the solution, the amount of isopropyl alcohol can be calculated as:
Isopropyl alcohol volume (mL) = (30.0 mL/100 mL) * 845 mL
The amount of water in the solution can be calculated as:
Water volume (mL) = Total volume of solution - Isopropyl alcohol volume
Therefore, the amount of isopropyl alcohol present in 845 mL of the solution is 253.5 mL, and the amount of water present is 591.5 mL.