Question

Write the ionic formulas for these ions:

A.) Barium (Ba) phosphide (P)
B.) Chromium (Cr) (IV) nitride (N)
C.) Lead (Pb) (IV) sulfide (S)"

Answer 1

The ionic formulas are Ba3P2 for barium phosphide, CrN2 for chromium(IV) nitride, and PbS2 for lead(IV) sulfide. Each ionic formula is determined by balancing the charges of the cations and anions.

Step-by-step explanation:

The ionic formulas for the given ions are:

1. Barium phosphide: Barium (Ba) has a +2 charge as it typically loses two electrons to achieve a noble gas configuration. Phosphorus (P) forms a -3 anion as phosphide (P3-). Therefore, in order to balance the charges, three barium ions are needed for every two phosphide ions to form barium phosphide, which has the formula Ba3P2.
2. Chromium(IV) nitride: Chromium with a +4 oxidation state (Cr4+) and nitride (N3-) will combine in a ratio that balances the total charges, resulting in the formula CrN2.
3. Lead(IV) sulfide: Lead (Pb) with a +4 charge (Pb4+) and sulfide (S2-) will combine in a 2:1 ratio of sulfide to lead, giving the formula PbS2.