Final answer:
Car A will pass Car B 3 seconds after starting, at a position 75 meters from the starting point.
Step-by-step explanation:
To determine where and when Car A passes Car B, we need to set up equations that represent the motion of both cars. We'll use the formula for distance, which is the product of velocity and time (distance = velocity × time).
The distance Car A travels can be expressed as: DA = vA × t, where vA is the velocity of Car A, and t is the time.
The distance Car B travels can be expressed as: DB = 60 m + vB × t, where 60 m is the initial position of Car B, and vB is the velocity of Car B.
Substituting the given velocities we get:
For Car A: DA = 25 m/s × t
For Car B: DB = 60 m + 5 m/s × t
To find the point where Car A passes Car B, we set DA equal to DB since they will have covered the same distance from the starting point:
25 × t = 60 + 5 × t
Solving for t gives us t = 3 seconds. Hence, Car A will pass Car B 3 seconds after both cars start moving.
The position where Car A passes Car B is found by substituting t = 3 s back into the equation for DA:
DA = 25 m/s × 3 s = 75 m
Therefore, Car A passes Car B at a position of 75 meters from the start.