Final answer:
The impulse applied to a 75 kg person who starts walking faster at 2.2 m/s due to a dog pulling on the leash is calculated by multiplying the mass (75 kg) by the change in velocity (2.2 m/s), resulting in an impulse of 165 kg m/s.
Step-by-step explanation:
The question asks about the impulse applied to a 75 kg person who starts walking faster at 2.2 m/s because a dog is pulling on the leash. Impulse is defined as the change in momentum, which can also be expressed as the product of the average force applied to an object and the time over which it is applied.
To calculate the impulse, we use the formula: impulse (J) = Δp = m Δv, where Δp is the change in momentum, m is the mass, and Δv is the change in velocity. Since we are looking for the initial impulse applied to start walking and assuming the person was initially at rest, the change in velocity (Δv) would be 2.2 m/s. The mass (m) of the person is 75 kg.
J = m Δv = 75 kg × 2.2 m/s
Therefore, J = 75 kg × 2.2 m/s = 165 kg m/s.