Final answer:
The type of bond that would form between Silver #47 and Bromine #35 is ionic.
Step-by-step explanation:
The type of bond that would form between Silver #47 and Bromine #35 is ionic. Bonds between a metal and a nonmetal are often ionic, and in this case, Silver (Ag) is a metal and Bromine (Br) is a nonmetal. Ionic bonding occurs when there is a transfer of electrons from a metal atom to a nonmetal atom, resulting in the formation of ions. In this case, Silver loses one electron to form a 1+ ion (Ag+) and Bromine gains one electron to form a 1- ion (Br-).
In this case, Silver would lose an electron to become Ag+ and Bromine would gain an electron to become Br−, resulting in the ionic compound AgBr.