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A plane flies 81.4 m/s 34.6° S of W. It encounters a wind blowing 34.4 m/s 12.5° E of N. What is the resultant vector (size and direction) of the plane?

User Sparkxxf
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Final answer:

To find the resultant vector of the plane's velocity and the wind's velocity, split each velocity into its x and y components. Add the x and y components separately, then use the Pythagorean theorem and inverse tangent to find the magnitude and direction of the resultant vector.

Step-by-step explanation:

To find the resultant vector, we need to add the vectors of the plane's velocity and the wind's velocity. We can break down each velocity into its x and y components. The plane's velocity is 81.4 m/s at an angle of 34.6° S of W. This can be split into x = 81.4 * cos(34.6°) and y = -81.4 * sin(34.6°). The wind's velocity is 34.4 m/s at an angle of 12.5° E of N. This can be split into x = 34.4 * sin(12.5°) and y = 34.4 * cos(12.5°). Now we can add the x and y components of the plane's velocity and wind's velocity separately to get the x and y components of the resultant vector. Finally, we can use the Pythagorean theorem and inverse tangent to find the magnitude and direction of the resultant vector.

The x component of the resultant vector is 81.4 * cos(34.6°) + 34.4 * sin(12.5°).

The y component of the resultant vector is -81.4 * sin(34.6°) + 34.4 * cos(12.5°).

The magnitude of the resultant vector is sqrt((x component)^2 + (y component)^2).

The direction of the resultant vector is arctan((y component) / (x component)).

User Emanuel Landeholm
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