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What is the probability of choosing a red marble without replacement and then choosing a red marble again from a box that contains 2 purple marbles, 2 blue marbles, 3 green marbles, and 5 red marbles?

User Palmin
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Final answer:

The probability of choosing a red marble without replacement and then choosing a red marble again is 5/33.

Step-by-step explanation:

To find the probability of choosing a red marble without replacement and then choosing a red marble again, we need to calculate the probability of each event separately and multiply them together.

First, there are 5 red marbles out of a total of 2 purple marbles, 2 blue marbles, 3 green marbles, and 5 red marbles, so the probability of choosing a red marble without replacement is 5/12.

Next, after taking out one red marble, the total number of marbles decreases to 11, and now there are 4 red marbles left. So the probability of choosing a red marble again is 4/11.

To find the probability of both events occurring, we multiply the probabilities: (5/12) * (4/11) = 20/132 = 5/33.

User Razzi Abuissa
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