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In a triangle with angles A measuring 65 degrees, B measuring 15 degrees, and C as x degrees, how are the sides arranged from shortest to longest?

Options:
A. BC, AC, AB
B. AB, AC, BC
C. BC, AB, AC
D. AC, BC, AB

User Rtacconi
by
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1 Answer

5 votes

Final answer:

In a triangle with angles measuring 65 degrees, 15 degrees, and x degrees, the sides are arranged from shortest to longest as BC, AC, AB.

Step-by-step explanation:

The sides in a triangle are arranged from shortest to longest based on the corresponding angles.

In this case, we have angle A measuring 65 degrees, angle B measuring 15 degrees, and angle C as x degrees.

Since angle B is the smallest, side BC will be the shortest.

Angle C is greater than angle A, so side AB will be longer than side AC.

Therefore, the sides are arranged in the following order from shortest to longest: BC, AC, AB.

User Elodie
by
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