Question

The school is selling tickets to wrestling matches. The first match, the school sold 10 general admission tickets and 3 student tickets for a total of $56. The second match, the school sold 4 general admission tickets and 6 student tickets for a total of $32. How much does each kind of ticket cost?

A)4g + 6s= 32
B)10g + 3s = 32
C)4g + 6s = 56
D)x + y = 32
E)10g + 3s = 56
F)x + y = 56

Answer 1

To find the cost of each kind of wrestling match ticket, solve the system of equations: 10g + 3s = 56 and 4g + 6s = 32, which represent the total ticket sales for the first and second matches, respectively.

Step-by-step explanation:

The question involves solving a system of linear equations to determine the price of each kind of a wrestling match ticket. We have two equations based on the information provided:

• For the first wrestling match: 10g + 3s = 56
• For the second wrestling match: 4g + 6s = 32

By solving this system of equations, we can find the individual prices for the general admission tickets (g) and the student tickets (s). Let's use substitution or elimination to solve for g and s. The correct representation of the problem is given by the options E (10g + 3s = 56) for the first match and A (4g + 6s = 32) for the second match.