Question

The moon has a mass of 7.35×10²2kg and a radius of 1.74×10⁶m . it orbits around the earth at a distance of 3.84×10⁸m , completing a full rotation every 27.3days . it also spins on its axis at a rate such that the same side of the moon is always facing the earth. what is the angular momentum, in newton seconds, of the moon in its orbit around earth? a) 7.34×10³³ b) 3.43×10²⁹ c) 2.71×10³³ d) 1.22×10³⁰

Answer 1

The angular momentum of the moon in its orbit around earth can be calculated using the formula L = I * w, where L is the angular momentum, I is the moment of inertia, and w is the angular velocity. Plugging in the values for the moon's mass, radius, and orbital velocity, we can calculate the angular momentum to be approximately 7.34x10^33 Newton seconds.

Step-by-step explanation:

To calculate the angular momentum of the moon in its orbit around the earth, we can use the formula:

L = I * w

Where L is the angular momentum, I is the moment of inertia, and w is the angular velocity. The moment of inertia can be calculated using the formula:

I = m * r^2

Where m is the mass and r is the distance from the axis of rotation. Plugging in the values for the moon's mass, radius, and orbital velocity, we can calculate the angular momentum to be approximately 7.34x10^33 Newton seconds (option a).