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Miranda knows the domain of f(x) is the set of positive real numbers. If she graphs f(x) on acordónate plane what must be true about the graph? The set of positive real numbers mean [0,oo). Posible answers: graph is entirely contained in quadrant l 2. The graph is entirely contained in quadrants l and ok. 3. The graph is entirely contained in quadrants l and lV. 4. The graph is entirely contained in quadrants ll and lll.

User Garmoncheg
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Final answer:

The graph of a function with domain [0,∞) must be entirely contained in quadrants I and IV of a two-dimensional coordinate plane because these are the regions where x is positive, in accordance with the function's domain.

Step-by-step explanation:

If Miranda knows that the domain of f(x) is the set of positive real numbers, which means [0,∞), and she graphs f(x) on a coordinate plane, then the graph must be entirely contained in quadrants I and IV. These are the quadrants where x takes on positive values. Quadrant I contains points where both x and y are positive, making it compatible with functions that have positive outputs. Quadrant IV, on the other hand, contains points where x is positive, but y is negative, suitable for functions with negative outputs. Since the domain is all positive real numbers, the x-values will never be negative, so the graph won't extend into quadrants II or III.

A straightforward example to consider is the graph of a constant function f(x) = 20 for 0 ≤ x ≤ 20. Here, the graph is a horizontal line at y = 20, stretching from the y-axis (x=0) to x=20. It is entirely contained within quadrant I because all x-values are positive and the y-value (f(x)) is also positive.

In cases of quadrants and graphing, it's important to know that the two-dimensional (x-y) graphing system is based on four quadrants, with the positive x-axis pointing right (towards quadrant I and IV) and the positive y-axis pointing up (towards quadrants I and II).

User Iamdual
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