Final answer:
The cost of each top is $20, and the cost of each bottom is $25. We used a system of linear equations to find the value of the tops and bottoms using the elimination method.
Step-by-step explanation:
To solve the problem of finding the cost of each top and each bottom, we'll need to set up a system of equations based on the information provided:
- 3 tops + 4 bottoms = $160
- 6 tops + 1 bottom = $145
We'll denote the cost of one top as T and the cost of one bottom as B. This gives us the following equations:
- 3T + 4B = 160
- 6T + B = 145
Now, we can solve this system using the substitution or elimination method. Let's use elimination. We can multiply the second equation by 4 to align the coefficients for B with the first equation:
- 3T + 4B = 160
- 24T + 4B = 580
Subtract the first equation from the modified second equation:
24T + 4B - (3T + 4B) = 580 - 160
21T = 420
T = 20 (Divide both sides by 21)
Now, we substitute T = 20 into the second original equation:
6(20) + B = 145
120 + B = 145
B = 25 (Subtract 120 from both sides)
Thus, the cost of each top is $20 and the cost of each bottom is $25.