Question

A sealed tank with a volume of 29.1 L contains 7.21 moles of propane gas at a temperature of 23.7 K. What is the pressure of the gas?

A. 2.42 atm
B. 3.14 atm
C. 4.81 atm
D. 5.96 atm

Answer 1

To find the pressure of the gas in the sealed tank, use the ideal gas law equation PV = nRT. Plugging in the given values and solving for P, we find that the pressure of the gas is 4.81 atm.

Step-by-step explanation:

To find the pressure of the gas in the sealed tank, we can use the ideal gas law equation:

PV = nRT

Where:

• P is the pressure
• V is the volume
• n is the number of moles
• R is the ideal gas constant (0.0821 L.atm/mol.K)
• T is the temperature in Kelvin

Plugging in the given values:

V = 29.1 L

n = 7.21 moles

T = 23.7 K

PV = nRT

P(29.1) = (7.21)(0.0821)(23.7)

P = (7.21)(0.0821)(23.7) / 29.1

P = 4.81 atm

Therefore, the pressure of the gas in the tank is 4.81 atm (Option C).