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The pressure of a 5.6631 mol sample of Oz in a 80.452 L container is measured to be 673.95

kPa. What is the temperature of this gas in kelvins?

User Emory
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Final answer:

To calculate the temperature of the gas in kelvins, we apply the ideal gas law PV = nRT using the given pressure, volume, and moles of the gas along with the proper gas constant for kPa. Rearrange the formula to solve for T and insert the values to obtain the temperature.

Step-by-step explanation:

The question asks for the temperature of a gas in kelvins using the ideal gas law. Given are the pressure of a 5.6631 mol sample of O2 (673.95 kPa), and the volume of the container (80.452 L). To find the temperature, we will use the ideal gas equation PV = nRT, where P is pressure, V is volume, n is number of moles of the gas, R is the gas constant, and T is temperature.

We need to use the R value that corresponds with the pressure unit kPa, which is approximately 8.314 kPa·L/mol·K. Rearranging the ideal gas equation to solve for T gives us T = PV/(nR). Substituting the given values into this equation yields:

T = (673.95 kPa × 80.452 L) / (5.6631 mol × 8.314 kPa·L/mol·K)

Performing the calculation provides us with the temperature in Kelvin.

User Carlo Bos
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