Final answer:
The pair of lines represented by the given equations is neither parallel nor perpendicular.
Step-by-step explanation:
To determine whether the pair of lines is parallel, perpendicular, or neither, we need to compare their slopes. The given equations are:
10 + 3x = 5y
5x + 3y = 1
To compare their slopes, we need to rewrite the equations in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept. Comparing the slopes, we can determine whether the lines are parallel, perpendicular, or neither.
Let's find the slope-intercept form for the first equation:
10 + 3x = 5y
3x - 5y = -10
-5y = -3x - 10
y = (3/5)x + 2
The slope of the first line is 3/5.
Now, let's find the slope-intercept form for the second equation:
5x + 3y = 1
3y = -5x + 1
y = (-5/3)x + 1/3
The slope of the second line is -5/3.
Since the slopes of the lines are not equal and not negative reciprocals of each other, the lines are neither parallel nor perpendicular. Hence, the answer is c) Neither.