Question

Find the rate of change for Five seconds after jumping out of the plane, a sky diver is 10,000 ft above the ground. After 30 seconds, the sky diver is 3750 ft above the ground​

Answer 1

The rate of change of the sky diver's altitude from 5 seconds to 30 seconds after jumping is an average velocity of 250 ft/s.

Step-by-step explanation:

To find the rate of change of the sky diver’s altitude, we can use the given information about the sky diver’s position at two different times. Initially, the sky diver is at 10,000 ft above the ground after 5 seconds of jumping. After 30 seconds, the sky diver is at 3,750 ft above the ground.

The rate of change in this context is the velocity of the sky diver, specifically the average velocity over the given time interval. To calculate this, we use the formula:

V = (Change in position) / (Change in time)

The change in position is 10,000 ft - 3,750 ft = 6,250 ft. The change in time is 30 seconds - 5 seconds = 25 seconds. So, the average velocity V is:

V = 6,250 ft / 25 s = 250 ft/s