Question

In Mr. Jones’s classroom, an assignment is graded for accuracy minus (1/4) of a point for each day the assignment is turned in late. If John received an 85 percent for accuracy but his grade was entered in as an 83.5, how many days late was the assignment?

A. Write the equation, using d to represent days that can be used to determine how many days late the assignment was turned in to Mr. Jones.
B. How late was the assignment?

Answer 1

John was six days late with his assignment. By setting up an equation and solving for the variable d, which represents the number of days late, we find that d equals 6.

Step-by-step explanation:

To calculate how many days late John's assignment was, we can set up an equation where d represents the number of days the assignment was late. We know that 85 percent is the original grade for accuracy and that 1/4 point is deducted for each day the assignment is late. John's adjusted grade is 83.5 percent after the late penalty has been applied.

The equation would look like this:

85 - (1/4)d = 83.5

Now, to find the value of d, we rearrange the equation to isolate d:

(1/4)d = 85 - 83.5

Then we simplify:

(1/4)d = 1.5

Multiplying both sides by 4 to solve for d:

d = 1.5 × 4

This gives us:

d = 6

So, John's assignment was 6 days late.