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Calculate the pressure of an ideal gas if you have 500 mL and 2.2 moles at a temperature of 23°C.

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Final answer:

The pressure of an ideal gas, we can use the ideal gas law equation PV = nRT. First, convert the volume from milliliters to liters and the temperature from Celsius to Kelvin. Then, plug the values into the ideal gas law equation and solve for pressure.

Step-by-step explanation:

To calculate the pressure of an ideal gas, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.


First, we need to convert the volume from milliliters to liters. Since 1 L = 1000 mL, the volume is 500 mL / 1000 = 0.5 L.


Next, we convert the temperature from Celsius to Kelvin. We add 273.15 to the Celsius temperature, so 23 °C + 273.15 = 296.15 K.


Now we can plug the values into the ideal gas law equation. P * 0.5 L = 2.2 moles * R * 296.15 K. Since R is a constant, we can rearrange the equation to solve for P: P = (2.2 moles * R * 296.15 K) / 0.5 L.


Let's assume the value of R is 0.08206 L * atm / (mol * K). Substituting this value in, we get P = (2.2 moles * 0.08206 L * atm / (mol * K) * 296.15 K) / 0.5 L = 199.267 atm.


Therefore, the pressure of the ideal gas is approximately 199.267 atm.

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