160k views
3 votes
Calculate the pressure of an ideal gas if you have 500 mL and 2.2 moles at a temperature of 23°C.

1 Answer

3 votes

Final answer:

The pressure of an ideal gas, we can use the ideal gas law equation PV = nRT. First, convert the volume from milliliters to liters and the temperature from Celsius to Kelvin. Then, plug the values into the ideal gas law equation and solve for pressure.

Step-by-step explanation:

To calculate the pressure of an ideal gas, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.


First, we need to convert the volume from milliliters to liters. Since 1 L = 1000 mL, the volume is 500 mL / 1000 = 0.5 L.


Next, we convert the temperature from Celsius to Kelvin. We add 273.15 to the Celsius temperature, so 23 °C + 273.15 = 296.15 K.


Now we can plug the values into the ideal gas law equation. P * 0.5 L = 2.2 moles * R * 296.15 K. Since R is a constant, we can rearrange the equation to solve for P: P = (2.2 moles * R * 296.15 K) / 0.5 L.


Let's assume the value of R is 0.08206 L * atm / (mol * K). Substituting this value in, we get P = (2.2 moles * 0.08206 L * atm / (mol * K) * 296.15 K) / 0.5 L = 199.267 atm.


Therefore, the pressure of the ideal gas is approximately 199.267 atm.

User AlexZeDim
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.