Final answer:
To find the new volume of a gas when temperature is reduced from 358 K to 220 K, assuming constant pressure and amount, Charles's Law is used giving a new volume of approximately 13.52 liters.
Step-by-step explanation:
The student has asked to find the new volume of gas when the temperature is reduced from 358 K to 220 K. Assuming that the pressure and the amount of gas remain constant, we can use Charles's Law for this calculation.
Charles's Law states that the volume of a gas is directly proportional to its temperature in kelvins, or V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, respectively, and V2 and T2 are the final volume and temperature.
To find the new volume (V2), we rearrange the formula to V2 = V1 * (T2/T1). Substituting the given values:
- V1 = 22 L (initial volume)
- T1 = 358 K (initial temperature)
- T2 = 220 K (final temperature)
We calculate:
V2 = 22 L * (220 K / 358 K)
V2 = 22 L * (0.6145)
V2 ≈ 13.52 L
Therefore, the new volume of the gas at 220 K will be approximately 13.52 liters.