Final answer:
The 32nd term of an arithmetic sequence is found using the formula and for this sequence, the 32nd term is 193. The options provided in the question do not include the correct answer, suggesting there might be an error.
Step-by-step explanation:
To find the 32nd term of the sequence 7, 13, 19, we first identify the pattern in the sequence. Each term increases by 6, so this is an arithmetic sequence with a common difference (d) of 6. The formula to find the nth term of an arithmetic sequence is given by:
an = a1 + (n - 1)d
Where a1 is the first term of the sequence and n is the position of the term in the sequence.
For this sequence:
- a1 = 7 (the first term)
- d = 6 (the common difference)
- n = 32 (we're seeking the 32nd term)
Plugging these values into the formula:
a32 = 7 + (32 - 1) × 6
a32 = 7 + (31 × 6)
a32 = 7 + 186
a32 = 193
However, 193 is not one of the given options, suggesting a typographical error in the options provided. Please review the question and the options for accuracy.