Question

What is the molarity of a solution with 2.3 grams of NaCl in 250ml of solution?

Answer 1

To find the molarity of a NaCl solution, firstly convert the mass of NaCl to moles and then divide by the volume of the solution in liters. In this case, the molarity is 0.157 M NaCl.

Step-by-step explanation:

To calculate the molarity of a solution with 2.3 grams of NaCl in 250 ml (0.250 liters) of solution, follow these steps:

1. Convert the mass of NaCl to moles using the molar mass of NaCl (58.44 g/mol):
   2.3 g × (1 mol / 58.44 g) = 0.03934 mol of NaCl.
2. Use the volume of the solution to calculate molarity:
   molarity (M) = moles of solute / liters of solution = 0.03934 mol / 0.250 L = 0.157 M NaCl.

Therefore, the molarity of the solution is 0.157 M NaCl.To determine the molarity of a solution, we need to calculate the number of moles of solute (NaCl) and then divide it by the volume of the solution in liters.

Step 1: Convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol.

2.3 g / 58.44 g/mol = 0.039 mol NaCl

Step 2: Convert the volume of the solution from milliliters to liters. 250 mL = 0.25 L.

Step 3: Use the formula: molarity (M) = moles of solute / volume of solution in liters.

Molarity = 0.039 mol / 0.25 L = 0.156 M