Answer:
Explanation:
sin(62°) = 25/BA
BA = 25/sin(62°) ≈ 28.3
Angle BAC = 180°-90°-62° = 28°
BC = √((BA)^2-(AC)^2) = 13.3
cosC = 0
Given ΔABC
The options:
A. 25/BA = sin 62° ⇒ BA = 25/sin 62° = 28.3 ≈ 28
B. ∠BAC = 90° - 62°= 28° ≠ 48°
C. 25/BC = tan 62° ⇒ BC = 25/tan 62° = 13.29 ≠ 18
D. cos(∠ACB) = 0 ⇒ cos 90° = 0
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