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Find the standard form of the equation of the parabola with a focus at (0, -10) and a directrix at

A. y = 10x^2
B.y = 40x^2

User Xtsoler
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1 Answer

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Final answer:

The standard form of the equation of the parabola with a focus at (0, -10) and a directrix at y = A is y = 5x^2 - 10.

Step-by-step explanation:

The standard form of the equation of a parabola with a focus at (0, -10) and a directrix at y = A can be found using the formula:

y = (1/4a)(x - h)^2 + k

where the vertex of the parabola is at the point (h, k) and the value of a can be determined using the distance between the focus and directrix. In this case, the distance is 20, so a = 1/4 * 20 = 5.

Substituting the values into the formula, we get:

y = (1/4 * 5)(x - 0)^2 + (-10)

y = 5x^2 - 10

Therefore, the standard form of the equation of the parabola is y = 5x^2 - 10.

User Knrz
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