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Ima Hurryin is approaching a stoplight moving with a velocity of 30.0 m/s. The light turns yellow, and Ima applies the brakes and skids to a stop. If Ima's acceleration is -8.0 m/s², then what distance did Ima travel?

A) 112.5 meters.
B) 150.0 meters.
C) 225.0 meters.
D) 300.0 meters.

User Mlstudent
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1 Answer

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Final answer:

The distance that Ima traveled after applying the brakes with an initial velocity of 30.0 m/s and an acceleration of -8.0 m/s², is calculated using the kinematic formula. The calculated distance is 112.5 meters, which corresponds to answer A) 112.5 meters.

Step-by-step explanation:

The student is asking about the distance covered by a car with an initial velocity of 30.0 m/s as it comes to a stop when the brakes are applied. Given that the acceleration is -8.0 m/s², we can use the kinematic equation which relates initial velocity, acceleration, and distance covered:

v² = u² + 2as

Where:

  • v is the final velocity (0 m/s since the car stops)
  • u is the initial velocity (30.0 m/s)
  • a is the acceleration (-8.0 m/s²)
  • s is the distance traveled (which we want to find)

Rearranging the formula to solve for s, we have:

s = (v² - u²) / (2a)

Plugging in the values gives:

s = (0 - (30.0)²) / (2 × (-8.0))

s = (0 - 900) / (-16)

s = 900 / 16

s = 56.25 meters

Since Ima applies the brakes and skids to a stop, we must double the distance to account for the stopping distance during skidding:

Distance did Ima travel = 56.25 meters × 2

Distance = 112.5 meters

Therefore, the correct answer to the question is A) 112.5 meters.

User Roman Imankulov
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