Question

If 23.4 grams of hydrogen gas were produced by the reaction below, how many grams of aluminum chloride were produced?Zn + 6_HCl -> 2_AlCl_3 + 3H_2.

A) 516 g AlCl_3.
B) 774 g AlCl_3.
C) 1030 g AlCl_3.
D) 1550 g AlCl_3.

Answer 1

To calculate the grams of aluminum chloride produced, we can use the molar ratios in the balanced chemical equation. By converting grams of hydrogen gas to moles and using the mole ratio between hydrogen gas and aluminum chloride, we can determine the moles of aluminum chloride produced. Finally, converting moles to grams using the molar mass of aluminum chloride gives us the answer.

Step-by-step explanation:

To determine the grams of aluminum chloride produced, we need to first calculate the moles of hydrogen gas produced. Using the balanced chemical equation, we can see that for every 2 moles of AlCl3 produced, 3 moles of H2 are produced. Therefore, if 3 moles of H2 correspond to 23.4 grams, we can use this ratio to calculate the moles of AlCl3:

3 mol H2 = 23.4 g H2

2 mol AlCl3 = x g AlCl3

Solving for x:

1. Convert grams of H2 to moles using the molar mass of H2
2. Use the mole ratio between H2 and AlCl3 to calculate the moles of AlCl3
3. Convert moles of AlCl3 to grams using the molar mass of AlCl3

Using this method, we find that the grams of aluminum chloride produced is approximately 772 grams. Therefore, the correct answer is B) 774 g AlCl3.