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A sample of gas has a volume of 168 mL at a temperature of 300 K. What would be the new volume of the gas if the temperature was lowered to 260 K? Assume the pressure does not change.

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Final answer:

Using Charles's Law, which states the direct proportionality of gas volume to its temperature at constant pressure, the new volume of a gas sample when temperature is decreased from 300 K to 260 K is calculated to be 145.6 mL.

Step-by-step explanation:

The question is asking us to determine the new volume of a sample of gas when its temperature is decreased, assuming constant pressure. This situation is governed by Charles's Law, which states that for a given amount of gas at constant pressure, the volume is directly proportional to its temperature in Kelvin. Charles's Law is mathematically represented as V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, respectively, and V2 and T2 are the final volume and temperature.

To find the new volume V2, you can rearrange the equation to V2 = (V1/T1) × T2. Substituting in the values given in the question, we have V2 = (168 mL / 300 K) × 260 K. Calculating this gives us V2 = 145.6 mL. Therefore, if the temperature of a gas sample is reduced from 300 K to 260 K with constant pressure, its volume decreases from 168 mL to 145.6 mL.

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