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A 0.250 L sample of seawater contains 77.4 g of NaCl, which has a molecular weight of 58.44. What is the molar concentration of sodium chloride in the seawater?

A) 0.400 M
B) 0.250 M
C) 0.300 M
D) 0.350 M

1 Answer

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Final answer:

The molar concentration of sodium chloride in the seawater sample is calculated to be 5.30 M by dividing the number of moles of NaCl (1.325 moles) by the volume of the solution (0.250 L).

Step-by-step explanation:

To determine the molar concentration of sodium chloride in seawater, use the following steps:

  1. First, calculate the number of moles of NaCl: 77.4 g of NaCl / 58.44 g/mol = 1.325 moles of NaCl.
  2. Next, convert 0.250 liters to liters, which is already in the correct unit, so it remains 0.250 L.
  3. Finally, calculate the molarity: Molarity (M) = moles of NaCl / liters of solution = 1.325 moles / 0.250 L = 5.30 M.

Therefore, the molar concentration of sodium chloride in the seawater is 5.30 M, which is not an option given in the question so potentially there could be a typo or misunderstanding in the question.

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