Question

If y = -2x^2 + 8x - 5 were put into vertex form, (y = a(x -h)^2 + k) what is the value of a, h, and K?

Answer 1

To put the equation y = -2x^2 + 8x - 5 into vertex form y = a(x - h)^2 + k, we need to complete the square. The value of a is -2, h is 2, and k is 3.

Step-by-step explanation:

To put the equation y = -2x^2 + 8x - 5 into vertex form y = a(x - h)^2 + k, we need to complete the square.

1. Factor out the common factor of -2 from the quadratic terms:

• y = -2(x^2 - 4x) - 5

Complete the square by adding and subtracting the square of half the coefficient of x:

• y = -2(x^2 - 4x + 4) - 5 + 8
• y = -2(x - 2)^2 + 3

Therefore, in vertex form, the value of a is -2, h is 2, and k is 3.