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What is the volume of 6.2x10^21 atoms of Ne?

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Final answer:

To calculate the volume of 6.2x10^21 atoms of neon, we first convert the number of atoms to moles using Avogadro's number, then multiply by the volume occupied by one mole at STP (22.4 L/mol) to get approximately 0.23072 liters.

Step-by-step explanation:

To calculate the volume of 6.2x1021 atoms of Ne (neon), we must first determine how many moles of neon these atoms represent. Using Avogadro's number, which is 6.022 x 1023 atoms per mole, we can convert the number of neon atoms to moles. The molar mass of neon is approximately 20.18 g/mol, and we know that one mole of a gas at standard temperature and pressure (STP) occupies 22.4 liters.

Firstly, we divide the number of atoms by Avogadro's number:

Number of moles = 6.2x1021 atoms / 6.022 x 1023 atoms/mole

This gives us approximately 0.0103 moles of neon.

Then, we can calculate the volume using the volume occupied by one mole of gas at STP:

Volume = Number of moles x Volume of one mole at STP

Volume = 0.0103 moles x 22.4 L/mol

Therefore, the volume of neon is approximately 0.23072 liters.

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