Question

What is the equation of the line passing through the points R(3, 3) and S(-6, -6) in standard form?

(A) x + y = 3
(B) x - y = 3
(C) y = x + 3
(D) y = -x + 3

Answer 1

The equation of the line passing through the points R(3, 3) and S(-6, -6) in standard form is x - y = 0.

Step-by-step explanation:

The equation of the line passing through the points R(3, 3) and S(-6, -6) can be found using the slope-intercept form. The slope of the line can be calculated using the formula: m = (y2 - y1) / (x2 - x1). Plugging in the coordinates of R(3, 3) and S(-6, -6), we get m = (-6 - 3) / (-6 - 3) = -9 / -9 = 1.

Next, we can use the slope-intercept form of a linear equation, y = mx + b, where m is the slope and b is the y-intercept. To find the y-intercept, we can substitute the coordinates of point R(3, 3) into the equation and solve for b: 3 = 1(3) + b, b = 3 - 3 = 0.

Therefore, the equation of the line passing through the points R(3, 3) and S(-6, -6) in standard form is y = x or x - y = 0. The correct answer is (B) x - y = 3.