Final answer:
None of the given answer choices (A) 1.44 x 10^23, (B) 1.44 x 10^22, (C) 1.44 x 10^21, (D) 1.44 x 10^20 matches the calculated number of ionic units for 7.2 x 10^-1 moles of MgCl2, which is approximately 1.30 x 10^23. A typo in the question or answers might be present.
Step-by-step explanation:
The question is asking how many ionic units are present in 7.2 x 10^-1 moles of MgCl2 (magnesium chloride).
First, we recognize that MgCl2 dissociates into three ions: one Mg2+ ion and two Cl- ions. Thus, one mole of MgCl2 generates three moles of ions. To find the total number of ionic units, we multiply the number of moles of MgCl2 by Avogadro's number, which is 6.022 x 10^23 units per mole, and then by 3 since we have 3 ionic units per mole of MgCl2.
7.2 x 10^-1 moles of MgCl2 x 3 (ionic units per mole of MgCl2) x 6.022 x 10^23 (units per mole) = 1.30 x 10^23 total ionic units.
However, since none of the given answer choices match the calculated value exactly, it is possible that there is a typographical error in the question or in the provided answer choices.