Question

A sample of nitrogen has a volume of 0.250L at a temperature of 22°C. What temperature would the sample have to be for the volume to increase to 280 mL ?

Answer 1

To solve this problem, we can use the combined gas law equation PV/T = constant. By rearranging the equation, we can find the final temperature. Plugging in the values, we find that the temperature would have to be 3346.6 K for the volume to increase to 280 mL.

Step-by-step explanation:

To solve this problem, we can use the combined gas law equation, which states that PV/T = constant. In this equation, P is the pressure, V is the volume, and T is the temperature in Kelvin. First, we need to convert the initial temperature of 22°C to Kelvin by adding 273.15. So the initial temperature is 295.15 K. Next, we can rearrange the equation to solve for the final temperature:

T_final = (V_final * T_initial) / V_initial

Now we can plug in the values:

T_final = (280 mL * 295.15 K) / 0.250 L = 3346.6 K

Therefore, the temperature would have to be 3346.6 K for the volume to increase to 280 mL.