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What is the probability of making 5 out of 5 field goals if the success rate is 75%?

User Dorbeetle
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Final answer:

To find the probability of making 5 out of 5 field goals with a 75% success rate, you can use the binomial probability formula. The probability is 0.2373, or 23.73%.

Step-by-step explanation:

To find the probability of making 5 out of 5 field goals with a 75% success rate, we can use the binomial probability formula. The formula is:

P(X=k) = C(n, k) * p^k * (1-p)^(n-k)

Where P(X=k) is the probability of getting k successes, n is the number of trials, p is the probability of success, and C(n, k) is the number of combinations of n things taken k at a time. In this case, n = 5, k = 5, and p = 0.75.

Using the formula, we can calculate the probability as follows:

  1. C(5, 5) = 1
  2. (0.75)^5 = 0.2373
  3. (1-0.75)^(5-5) = 1
  4. P(X=5) = 1 * 0.2373 * 1 = 0.2373

The probability of making 5 out of 5 field goals with a 75% success rate is 0.2373, or 23.73%.

User JeeBee
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