Question

What is the equation in slope-intercept form of a line that passes through the point (4, 5) and has a slope of 12 ?

Enter your answer by filling in the blanks.
y=____x + ____

A. y = 12x - 43
B. y = 43x - 12
C. y = 12x + 43
D. y = -12x + 43

Answer 1

The equation of a line with a slope of 12 that passes through the point (4, 5) is y = 12x - 43. This is found using the slope-intercept form y = mx + b.

Step-by-step explanation:

The equation of a line in slope-intercept form is given by y = mx + b, where m represents the slope of the line, and b represents the y-intercept of the line. Given a slope of 12 and the point (4, 5) through which the line passes, we can plug these values into the slope-intercept form equation to find b.

Using the point (4, 5), the equation becomes 5 = 12(4) + b, which simplifies to 5 = 48 + b. Solving for b, we get b = 5 - 48, resulting in b = -43.

Therefore, the equation of the line is y = 12x - 43.

The correct answer is A. y = 12x - 43.