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What is the average rate of change of the bee during the interval 10 < t < 12?

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Final answer:

The average rate of change over an interval is the change in value divided by the length of the interval. For the interval 10 < t < 12, you would find the difference in the quantity's value at t = 10 and t = 12 and divide by 2.

Step-by-step explanation:

The average rate of change of a quantity over an interval is calculated by taking the difference in the quantity's value at the end of the interval and the beginning, and then dividing by the length of the interval. Specifically, for the given interval of 10 < t < 12, you would subtract the value of the distance at t = 10 from the value at t = 12, and divide by 2 (because 12 - 10 = 2).

In a broader sense, if this were a question about chemistry or physics, the method would be analogous, with the quantity in question changing accordingly (e.g., concentration of a substance in chemistry or current in physics). However, the provided information seems fragmented and it isn't clear what the specific subject or context of the bee's movement is. Assuming it is related to position over time, you could use a position vs. time graph to determine the average velocity, similar to the calculation of the average rate of chemical reactions or growth mentioned in the provided examples.

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