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What is the acceleration of a 2.3 kg toy car that experiences a 25 N force pushing it forward and 6.8 N of friction pushing it back?

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Final answer:

The acceleration of the 2.3 kg toy car with a net force of 18.2 N (after subtracting the frictional force) is 7.91 m/s².

Step-by-step explanation:

The acceleration of a toy car can be calculated using Newton's second law of motion, which states that the net force acting on an object equals its mass times its acceleration (F = ma). In this question, the toy car with a mass of 2.3 kg experiences a forward force of 25 N and a frictional force of 6.8 N opposing the motion.

First, we calculate the net force acting on the car by subtracting the frictional force from the forward force:

  • Net force = Forward force - Frictional force
  • Net force = 25 N - 6.8 N
  • Net force = 18.2 N

Next, we use the net force and the mass of the car to find the acceleration:

  • Acceleration (a) = Net force / Mass
  • Acceleration (a) = 18.2 N / 2.3 kg
  • Acceleration (a) = 7.91 m/s²

The acceleration of the toy car is 7.91 m/s².

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