75.7k views
5 votes
If 3x^3 = 15, what is the smallest possible value of x?

A) -8
B) -6
C) -5
D) -4

User Carewithl
by
7.3k points

1 Answer

2 votes

Final answer:

The smallest possible value of x for the equation 3x^3 = 15 is the negative cube root of 5, which is not listed in the provided options, indicating that none of the choices are correct.

Step-by-step explanation:

To find the smallest possible value of x when 3x^3 = 15, we start by dividing both sides of the equation by 3, which gives us x^3 = 5. To solve for x, we take the cube root of both sides, yielding x = √[3]{5}. Since we are looking for the smallest possible value, we consider the negative cube root as well, which is x = -√[3]{5}. Therefore, the smallest possible value of x that satisfies the equation is negative, and among the options given, the closest value to -√[3]{5} without going over is -2, which is not listed among the options provided. Thus, none of the provided choices are correct.

User Justin Braaten
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.